22. Riemann Sums, Integrals and the FTC
c. Indefinite Integrals
The Fundamental Theorem of Calculus tells us that \(\displaystyle I_a(x)=\int_a^x f(x)\,dx\) is a particular antiderivative of \(f(x)\). Each choice of \(a\) gives us a different antiderivative. If we don't specify the \(a\), we get the general antiderivative. This motivates the following definition:
The general antiderivative of a function \(f(x)\) is also called the indefinite integral of \(f(x)\) and is denoted by \[ \int f(x)\,dx \] with no limits on the integral sign. Thus if \(F(x)\) is any particular antiderivative of \(f(x)\), then \[ \int f(x)\,dx=F(x)+C \] where \(C\) is an arbitrary, unspecified constant, called the constant of integration.
The constant of integration can be any letter. \(C\) is just conventional.
For example, since \(\dfrac{d}{dx}(x^2-2x)=2x-2\), we can write \[ \int (2x-2)\,dx=x^2-2x+C \] However, since (by the Chain Rule) we also have \(\dfrac{d}{dx}(x-1)^2=2(x-1)=2x-2\), we can also write \[ \int (2x-2)\,dx=(x-1)^2+C \] There is no contradiction here because \(x^2-2x\) and \((x-1)^2=x^2-2x+4\) just differ by a constant, so that the two formulas for the indefinite integral just have a different meaning for \(C\).
Compute the indefinite integral \(\displaystyle \int \cos x\,dx\).
\(\displaystyle \int \cos x\,dx=\sin x+C\)
Since \(\dfrac{d}{dx}(\sin x)=\cos x\), we can write \[ \int \cos x\,dx=\sin x+C \]
Heading
Placeholder text: Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum Lorem ipsum